SOLUTION: If (-10,-2), (-3,4), and (6,4) are coordinates of three vertices (corners) of a parallelogram, determine the coordinates of three different points that could serve as the fourth ve

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Question 980247: If (-10,-2), (-3,4), and (6,4) are coordinates of three vertices (corners) of a parallelogram, determine the coordinates of three different points that could serve as the fourth vertex.
My answer was (-1,-2), (-20,-2), and (-13,4). The books answer was (-1,-2), (-19,-2), and (13,10). I drew the graph with my three points and it has the shape of the parallelogram. Let me know if I'm right or help me if I'm wrong.
Found 2 solutions by Alan3354, AnlytcPhil:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
If (-10,-2), (-3,4), and (6,4) are coordinates of three vertices (corners) of a parallelogram, determine the coordinates of three different points that could serve as the fourth vertex.
My answer was (-1,-2), (-20,-2), and (-13,4). The books answer was (-1,-2), (-19,-2), and (13,10). I drew the graph with my three points and it has the shape of the parallelogram.
-------------------
(-13,4) doesn't work
(-20,-2) is close, 1 unit off is all.
Answer by AnlytcPhil(1807)   (Show Source): You can put this solution on YOUR website!
Get some graph paper. 



Notice that to go from (6,4) to (-3,4) you go 9 units left.
Therefore you go 9 units left from (-10,-2) and end up at (-19,-2)





From (-10,-2) to (-3,4) you have to go right 7 units and up 6. So you start at
(6,4) and do the same -- go right 7 and up 6, and you end up at (13,10)




If you put all those together on one graph, you have a triangle with the midpoints of the sides connected.



Edwin
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