SOLUTION: At what "x" value does the parabola y=x^2-5x+4 intersect the x axis?
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Question 979877: At what "x" value does the parabola y=x^2-5x+4 intersect the x axis?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
To find where a parabola cuts the
'x' axis make y = 0
Factorise x^2 - 5x + 4 = 0
(x - 1)(x - 4) = 0
Therefore,
x - 1 = 0
x = 1
or
x - 4 = 0
x = 4
Hope this helps:-)
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