SOLUTION: Hi, I need help!!!! I'm confused with these two questions and don't know where to begin. CV

Algebra.Com
Question 977950: Hi, I need help!!!! I'm confused with these two questions and don't know where to begin.
CV

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
5x + 3y = 7
y - 4 > 0
Graph as 3y=-5x+7;; y= -(5/3)x + (7/3)
That is a line.
The other line is y>4. That is a horizontal line where y=4.
The solution to this problem, assuming that both equations have to be satisfied, lies ON the line ABOVE y=4, not including the point where y=4.

RELATED QUESTIONS

I am in need of some help, this is my first statistics class and we are in the second... (answered by stanbon)
HI I NEED HELP WITH A QUESTION I DON;T KNOW TO REACH THE CONCLSUION I KNOW NOTHING ABOUT... (answered by Alan3354)
Hi, I'm having trouble with my homework and I was hoping you could help. In the first (answered by scott8148)
hi i really need help with this one problem I do not know where to begin. Thank you so... (answered by ankor@dixie-net.com)
hi, i need your help please... i don't know how to answer these questions because i can't (answered by Theo,ikleyn,greenestamps,n2)
I need to know where to put 24/3 on a number line. I know that is equal to 8 but I don't... (answered by CubeyThePenguin)
I need help with this. I don't know where to begin. Factor:... (answered by checkley71,cowess)
10x^5+11x^4+3x^3 I have to factor by grouping and ac method please help I don’t know what (answered by KMST)
With these two problems, I am very confused, because math is not my thing, and I do not... (answered by ankor@dixie-net.com,mangopeeler07)