SOLUTION: write the equation of the line that is perpendicular to the line x-3y=2 and passes through the point (0,4)

Question 976070: write the equation of the line that is perpendicular to the line x-3y=2 and passes through the point (0,4)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x-3y=2
rewrite in slope intercept form and just get the slope
-3y=-x+2
divide by (-3)
y= (x/3)-(2/3)
The perpendicular line has a slope of -3, the negative reciprocal.
point slope formula
y-y1=m(x-x1)
y-4 = -3x
y=-3x+4

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