SOLUTION: The graph of y = n ( 1−x^2 ) has an area equal to 51, find the value of n.

SOLUTION: The graph of y = n ( 1−x^2 ) has an area equal to 51, find the value of n.

Algebra.Com

Question 973693: The graph of y = n ( 1−x^2 ) has an area equal to 51, find the value of n.
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
first find the zeros for 1 - x^2
(1+x)(1-x) = 0
zeros are -1, 1
integrate 1 - x^2
integral = x - x^3/3
evaluate the integral for x = -1 and 1
(1 - 1/3) - (-1 + 1/3) = 2/3 + 2/3 = 4/3
we are given
51 = n * 4/3
4n = 153
n = 38.25

RELATED QUESTIONS
The graph of y = n ( 16−x2 ) is shown. http://imgur.com/sBaSvn9 If the... (answered by rothauserc,Alan3354)

Find the values of n when x^2 − 3x − n = 0 has two... (answered by htmentor,Alan3354)

A sequence has its first term equal to 4, and each term of the sequence is obtained by... (answered by ikleyn)

Hi How exactly do I do b + c of this question? a) Using a large scale, sketch the... (answered by stanbon)

If an N x N square has area 32, what is the area of an (N-2) x (N+2) rectangle?... (answered by josgarithmetic)

find the exact positive value of c which makes the area under the graph of y=c(1-x^2)and... (answered by Alan3354)

the range of the equation y - 5 = 2|x+2| is y is greater than or equal to n. what is the... (answered by solver91311)

Consider the random graph G(n,p) on n vertices, where the probability of an edge between... (answered by ikleyn)

For positive integer values of N, let N be defined as: N = 2 + 4 + 6 + ... + N, if N (answered by Edwin McCravy)