SOLUTION: can anyone help me? A walker walks a course at a constant speed of 4 mph. 40 min after the walker begins, a cyclist starts on the same course at a constant speed of 16 mph. how

Question 9734: can anyone help me?
A walker walks a course at a constant speed of 4 mph. 40 min after the walker begins, a cyclist starts on the same course at a constant speed of 16 mph. how long after the cyclist begins does the cyclist overtake the walker? What distance have they traveled? Has teh walker completed the course before the cyclist catches up?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
For the walker:
r1 = 4 mph
t1 = t2 + 2/3 hrs. (40 mins = 2/3 hrs)
For the cyclist:
r2 = 16 mph

When they meet, d1 = d2.
Simplify and solve for t2
Subtract 4*t2 from both sides.
Divide both sides by 12.

t2 = 2/9 hours They will meet 2/9 hrs (13.3... mins) after the cyclist starts.
They will have traveled a distance of d1 = 16*t2 or 16 mph(2/9 hrs) = 3.56 miles.
Has the walker completed the course? Who knows! How long is the course?
Check:

miles.

miles.

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