SOLUTION: determine the equation of the line, in slope-intercept form, that contains the points
(-5,9) and (-5,-2)
Algebra.Com
Question 96754: determine the equation of the line, in slope-intercept form, that contains the points
(-5,9) and (-5,-2)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First lets find the slope through the points (,) and (,)
Start with the slope formula (note: )
is the first point (,) and )
is the second point (,))
Plug in ,,, (these are the coordinates of given points)
Subtract the terms in the numerator to get . Subtract the terms in the denominator to get
Since the denominator is zero, the slope is undefined (remember you cannot divide by zero). So we cannot use the slope intercept form to write an equation. So we can only say that the equation is a vertical line through , which means the equation is (notice this is not in slope-intercept form)
So the equation looks like this:
Graph of through the points (,) and (,)
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