SOLUTION: I'm don't understanding how to solve this question: The graph of a line passes through the x-intercept of y-20=2/11(x-31) and is perpendicular to the line y=1/7x+7 . The equati

Question 957503: I'm don't understanding how to solve this question:
The graph of a line passes through the x-intercept of y-20=2/11(x-31) and is perpendicular to the line y=1/7x+7 . The equation of the line, written in Slope-Point form, is y-p = m(x-q). what is the value of m*q ?
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
First find the x-intercept of

So solve for when

So the x-intercept is (-79,0).
.
.
.
Perpendicular lines have slopes that are negative reciprocals.

So then using the point-slope form,

RELATED QUESTIONS
How do I write in slope-intercept form for the line that satisfies the condition with a... (answered by stanbon,lwsshak3)

Quick question. 23-(x-7) Trying to understand how this is solved. I know the... (answered by josgarithmetic)

In advance I apologize for this long question and also thank you for helping me. Use... (answered by josgarithmetic)

Ok, shhhhhhhhhhh I am a 48 year old, 26 year veteran second grade teacher taking a math... (answered by stanbon,josmiceli)

Please solve this question which i have taken from the book (applied mathematics of... (answered by richwmiller)

I have two questions, having to write an equation in standard form for each line... (answered by solver91311)

the graph of f passes through point (-1 2) and is perpendicular to the line that has an x (answered by ReadingBoosters)

A line l is parallel to the y-axis and passes through the point (2,3). What is its... (answered by rothauserc)

A line has the x-intercept 12 and y-intercept 7. The slope of the line is m = ? (answered by Fombitz)