SOLUTION: 3y/2+y/6=10/3 solve the linear equation?
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Question 95472: 3y/2+y/6=10/3 solve the linear equation?
Found 3 solutions by stanbon, edjones, jayanthihemkos@yahoo.com:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3y/2+y/6=10/3 solve the linear equation
Multiply thru by 6 to get:
6y + y = 20
7y=20
y = 20/7
================
Cheers,
Stan H.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
multiply 6 times both sides to get rid of the fractions. 9y+y=20
10y=20
divide 10 into both sides. y=2
Check:
LCD=6
EdJones
Answer by jayanthihemkos@yahoo.com(87) (Show Source): You can put this solution on YOUR website!
3y/2+y/6=10/3 solve the linear equation?
L.C.D of 2, 6 , 3 is 6
Multiply the equation by 6
3y/2*6+y/6*6=10/3*6
Multiplying by the L.C.D will remove the fraction
3y *3 + y = 20
9y +y = 20
10y = 20
10y/10 = 20/10
y = 2
check
consider the equation and pluggin the value of y in it
3y/2+y/6=10/3
3(2)/2 +2/6 = 10/3
6/2 +2/6 = 10/3
3 +1/3 = 10/3
(3*3 +1)/3 = 10/3
(9+1)/3 = 10/3
10/3 = 10/3
LHS = RHS
Hence y = 2 is the solution
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