SOLUTION: Sketch the straight line defined by the linear equation by finding the x- and y- intercepts
5x-3y+15 =0
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Question 954460: Sketch the straight line defined by the linear equation by finding the x- and y- intercepts
5x-3y+15 =0
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
5x-3y+15 =0
x-intercept:
5x+15=0
5x=-15
x=-3
y-intercept:
-3y+15=0
-3y=-15
y=5
.
GRAPH:
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