SOLUTION: I have to write an equation for a line that is a)parallel to 4x-2y=3 that goes through the Point (2,1) and b) perpendicular to 4x-2y=3 and goes through said point, and both have to

Question 95225This question is from textbook Precalculus With Limits
: I have to write an equation for a line that is a)parallel to 4x-2y=3 that goes through the Point (2,1) and b) perpendicular to 4x-2y=3 and goes through said point, and both have to be in general form, but I have no idea how to do anything in general form - my previous math classes didn't go over it, and my current one thinks that everyone knows how to do it. Please help?! This question is from textbook Precalculus With Limits

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
general form means Ax+By+C=0, where A, B, and C are integers ... do the calculations and convert at the end

original equation in slope-intercept is y=2x-(3/2) so slope is 2

parallel line has same slope ... point-slope gives y-1=2(x-2) ... y-1=2x-4 ... 2x-y-3=0

perpendicular slope is negative reciprocal ... point-slope gives y-1=(-1/2)(x-2) ... y-1=(-1/2)x+1 ... x+2y-4=0
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