SOLUTION: Solving a word problem using a system of linear equations: the combined cost of one advance ticket to a show and one same-day ticked was $45. it is known that 25 tickets were sol

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Question 94633This question is from textbook ALEKS(on line)
: Solving a word problem using a system of linear equations:
the combined cost of one advance ticket to a show and one same-day ticked was $45. it is known that 25 tickets were sold in advance and 15 the same day, for the total receipts of $825
What was the price of tickes sold in advance by y:
this is what I do know:
x+y=45
15x+25y=825
the answer is x=$30 y=15
But I dont know what they did to 15x+25y=825 to get the answer.
I was subtracting 25y from each side and then dividing to get Y and that isn't working for me.
This question is from textbook ALEKS(on line)

Answer by stanbon(57246) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=45
15x+25y=825
the answer is x=$30 y=15
But I dont know what they did to 15x+25y=825 to get the answer
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x = 45-y
Substitute so you can solve for y, as follows:
15(45-y) + 25y = 825
675 - 15y + 25y = 825
10y = 150
y = $15 (price of a same-day ticket)
45-15 = $30 (price of an advanced-sale ticket)
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Cheers,
Stan H.