SOLUTION: For the problem given below, set up an equation and solve. Show all work (including what your variables represent), detailing each step, to ensure that I am able to follow your wo

Question 941776: For the problem given below, set up an equation and solve. Show all work (including what your variables represent), detailing each step, to ensure that I am able to follow your work. Clearly state your solution. Please and thank you
The problem:
If the product of two consecutive positive even integers is equal to 168, then what are the integers.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
Two consecutive even integers, I and I+2
Product is 168, (I)(I+2)=168
Subtract 168 from each side

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=676 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 12, -14. Here's your graph:

The results are 12 and -14. The integer specified is positive, so I=12 and the second is I+2=14
CHECK:the product of 12 and 14 is (12)(14}=168
The ANSWER (SOLUTION) Is 12 and 14

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