SOLUTION: determine the equation of the line containing the points (0,2) and (2,0) when i did this problem i did y2-y1/x2-x1 and got 0-2/2-0 then got -2/0 then got 0 for my slope. then i cho

Question 94114: determine the equation of the line containing the points (0,2) and (2,0) when i did this problem i did y2-y1/x2-x1 and got 0-2/2-0 then got -2/0 then got 0 for my slope. then i chose the point (0,2) and got my answer y-2=0(x-0) so is that correct? if not what did i do wrong?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First lets find the slope through the points (,) and (,)

Start with the slope formula (note:

is the first point (,) and

is the second point (,))

Plug in ,,, (these are the coordinates of given points)

Subtract the terms in the numerator to get . Subtract the terms in the denominator to get

Reduce

So the slope is

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Now let's use the point-slope formula to find the equation of the line:

------Point-Slope Formula------
where is the slope, and

is one of the given points

So lets use the Point-Slope Formula to find the equation of the line

Plug in , , and (these values are given)

Distribute

Multiply and to get

Add to both sides to isolate y

Combine like terms and to get
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Answer:

So the equation of the line which goes through the points (,) and (,) is:

The equation is now in form (which is slope-intercept form) where the slope is and the y-intercept is

Notice if we graph the equation and plot the points (,) and (,), we get this: (note: if you need help with graphing, check out this solver )

Graph of through the points (,) and (,)

Notice how the points lie on the line. This graphically verifies our answer.
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