SOLUTION: Write the equation of the line that satisfies the given conditions. Express the final equation in standard form.
Contains the origin and is perpendicular to the line -4x + 3y = 8
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Question 938704: Write the equation of the line that satisfies the given conditions. Express the final equation in standard form.
Contains the origin and is perpendicular to the line -4x + 3y = 8
Found 2 solutions by LinnW, ewatrrr:
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
Find the slope of -4x + 3y = 8 by solving for y
add 4x to each side
3y = 4x + 8
divide each side by 3
y = (4/3)x + 8/3
The slope of a line perpendicular will be
the negative inverse of 4/3 which is -3/4
Since the perpendicular goes through (0,0) ,
using the template y = mx + b , y = 0 , m = -3/4 and x = 0
0 = (-3/4)(0) + b
0 = b
y = (-3/4)x + 0
y = (-3/4)x
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
the standard slope-intercept form for an equation of a line is
where m is the slope and b the y-intercept.
-4x + 3y = 8 0r y = (4/3)x + 8/3, m = (4/3)
....
Line perpendicular(Slope is the negative reciprocal): m = (-3/4)
...
***Using point-slope form, P(0,0)
y-0 = (-3/4)(x-0)
y = (-3/4)x
Standard Form: 3x + 4y = 0
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