SOLUTION: Hi I am needing a little help on some algebra. Could you help me solve this: Is the point (-120,-99) on the graph of the line. Y=4/5x-3? Explain why or why not. I have tried and

Question 93334: Hi I am needing a little help on some algebra. Could you help me solve this:
Is the point (-120,-99) on the graph of the line. Y=4/5x-3? Explain why or why not. I have tried and can't come up with anything. Thanks for your time
Found 2 solutions by Earlsdon, bucky:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Is the point (-120, -99) on the graph of ?
If the given point is on the line then the x- and y-coordinates of the point will satisfy the equation.
To find out if this is true, you will substitute the x- and y-coordinates of the point (-120, -99) into the equation.
Evaluate this.

The answer is yes.
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
The point (-120,-99) is in the standard form (x,y) which means x = -120 and y = -99.
If that point is on the graph of the line that represents the equation:
.

.
then if you substitute -99 for y and -120 for x both sides of the equation will be
equal and that will prove that the point is on the line. Let's try it ...
.
Substituting -99 for y and -120 for x changes the equation to:
.

.
If you multiply you multiply the 4 times the -120 to get -480 and then you
divide that by the denominator 5 to get -96. Substituting -96 for
the equation then becomes:
.

.
and on the right side if you combine -96 and - 3 you get -99. That reduces the equation to:
.

.
Both sides of the equation are equal when x = -120 and y = -99.
.
This shows the equation is true for the point (-120,-99). Therefore, since the x and y values
of the point make the equation true, you can say that the point (-120,-99) is on the graph
of the equation:
.

.
Hope this helps you to understand the problem and what you have to do to show whether
points are or are not on the graph of an equation.
.
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