SOLUTION: Find the value of k so that the point (-2,10) is on the line y=kx-3k

Question 928171: Find the value of k so that the point (-2,10) is on the line y=kx-3k
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
m = slope
---
use the point-slope form of the line with the given point (-2,10):
y - 10 = m(x + 2)
y = mx + 2m + 10
y = mx + (2m + 10)
---
equate to the given linear form:
kx - 3k = mx + (2m + 10)
---
equate "like" terms:
---
equate the x terms:
mx = kx
m = k
k = m
---
equate the constant terms:
-3k = (2m + 10)
k = (2m + 10)/-3
---
equate the k expressions:
m = (2m + 10)/-3
-3m = 2m + 10
-5m = 10
m = -2
---
answer:
k = -2
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Convert fractions, decimals, and percents:
https://sooeet.com/math/fraction-decimal-percent.php
---
Calculate and graph the linear regression of any data set:
https://sooeet.com/math/linear-regression.php
RELATED QUESTIONS
Find the value of k so that the line kx-5y=21 will contain the point... (answered by Edwin McCravy)

(x+2k)^2 + (y-3k)^2 = 25 pass through the point (1,0) find value of... (answered by Alan3354,MathLover1)

pls help me to answer with solution ; what is the value of k so that the line... (answered by Fombitz,Theo)

Find value(s) of k such that y=kx-3 is tangent to the parabola y=2x^2+... (answered by Edwin McCravy)

Find the value of k so that the point (k,k) lies on the line... (answered by jim_thompson5910)

What must be the value of k so that 5k - 3, k + 2, 3k -... (answered by Boreal)

find the value of k so that the line contains (4, -3k) and (2k,5) has a slope of m =... (answered by stanbon)

find the value of k so that the graph of kx+3y=4 is parallel to the line through (2,-k)... (answered by reviewermath)

Find the value of K so that the given line has slope m. kx-3y=7 m=2 (answered by gonzo)