SOLUTION: 36. lines through (-2,0) with slope -3/4. 38. line through (0,9) that is parallel to the line 3x + 5y =15. 40. line through (-2,4) that is perpendicular to the x-axis. 42.

Algebra ->  Linear-equations -> SOLUTION: 36. lines through (-2,0) with slope -3/4. 38. line through (0,9) that is parallel to the line 3x + 5y =15. 40. line through (-2,4) that is perpendicular to the x-axis. 42.      Log On


   

Question 92782: 36. lines through (-2,0) with slope -3/4.
38. line through (0,9) that is parallel to the line 3x + 5y =15.
40. line through (-2,4) that is perpendicular to the x-axis.
42. slope intercept form. y + 2 = -6 (x-1)
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
36) THE LINE FORMULA IS:
Y=mX+b WHERE (m)=SLOPE & (b)=Y INTERCEPT.
NOW SUBSTITUTE THE X & Y POINTS & SOLVE FOR THE Y INTERCEPT (b).
0=-3/4*-2+b
0=6/4+b
b=-6/4
b=-1.5 FOR THE Y INTERCEPT. THUS THE LINE EQUATION IS:
Y=-3X/4-1.5 OR Y=-.75X-1.5 ANSWER.
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38) 3X+5Y=15
5Y=-3X+15
Y=-3X/5+15/5
Y=-.6X+3
THUS A LINE PARALLEL TO THIS LINE & PASSING THROUGH (0,9) HAS A SLOPE OF -.6. NOW SUBSTITUTE THE X & Y POINTS (0,9) & SOLVE FOR THE Y INTERCEPT.
9=-.6*0+b
b=9 IS THE Y INTERCEPT.
THUS THE EQUATION FOR THIS LINE IS Y=-.6X+9
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2 SOLUTIONS. NOW YOU FINISH THE HOMEWORK. :-)