SOLUTION: A collection of dimes and nickels is worth $9.50. There are 132 coins in all.
How many of each coin are there?
dimes
nickels
Algebra.Com
Question 918257: A collection of dimes and nickels is worth $9.50. There are 132 coins in all.
How many of each coin are there?
dimes
nickels
Answer by AlgebraLady88(44) (Show Source): You can put this solution on YOUR website!
We are told that a collection of dimes(x) and nickels(y) equals 132 coins in all.
The algebraic equation for that would be
x + y = 132 (1)
We are also told that all the coins add up to $9.50. The algebraic equation for that would be
0.10 x + 0.05 y = 9.50 (2)
Now we will multiply the above equation by 100 to get rid of the decimals, giving us :
10 x + 5 y = 950 (3)
Now we will multiply equation (1) by 5 , giving us
5 x + 5 y = 660 (4)
Now, we subtract : (3) - (4)
5x = 290
x = 58
This will give us y = 74.
To check , 58 ( 0.10) + 74 ( 0.05) = 9.50
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