SOLUTION: For some real number A, the graph of the liney=(A+1)x+8 in the standarsd (x,y) coordinate plane passes through (2,6). What is the slope.
A.)-4
B.)-3
C.)-1
D.)3
E.)7
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Question 912199: For some real number A, the graph of the liney=(A+1)x+8 in the standarsd (x,y) coordinate plane passes through (2,6). What is the slope.
A.)-4
B.)-3
C.)-1
D.)3
E.)7
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
It passes through (2,6) so (x,y) = (2,6)
y=(A+1)x+8
6=(A+1)(2)+8 ... plug in (x,y) = (2,6)
6=2A+2+8
6=2A+10
6-10=2A
-4=2A
-4/2=A
-2=A
A = -2
Use this to find the slope
m = A+1
m = -2+1
m = -1
The slope is -1.
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