SOLUTION: The lines with equations 5x+3y=4 and 2kx-5y=10 are perpendicular. what is the value of k?

Question 911953: The lines with equations 5x+3y=4 and 2kx-5y=10 are perpendicular. what is the value of k?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The lines with equations 5x+3y=4 and 2kx-5y=10 are perpendicular
what is the value of k?
:
Put both equations in the slope intercept form
5x + 3y = 4
3y = -5x + 4
y = x +
:
2kx - 5y = 10
-5y = -2ks + 2
Divide both sides by -5
y = x - 2
:
The slope relationship of perpendicular lines: m1 * m2 = -1, therefore:
* = -1
= -1
multiply both sides by 15
-10k = -15
k = -15/-10
k = +1.5
Therefore the 2nd equation:
y = x - 2
y = x - 2
:
;
See if the relationship between the two slopes is -1
* = -1
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