SOLUTION: The length of a rectangle is 3 feet more than 4 times its width and its width is 50 feet. A) Find the Area of the rectangle. B) Find the perimeter. C) Draw this rectangle on a coor

Question 910687: The length of a rectangle is 3 feet more than 4 times its width and its width is 50 feet. A) Find the Area of the rectangle. B) Find the perimeter. C) Draw this rectangle on a coordinate plane and write the 4 ordered pairs of the vertices of the rectangle (be sure to label axis and use appropriate units of measure.
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
P = 2L + 2W
L = 4W + 3
W = 50
If the width is 50, then the length is (4*50)+3, or 203
Area = Length * width
Area = 203 * 50 = 10,150
Perimeter = 2(203) + 2(50) = 406 + 100 = 506
You'll have to draw it yourself as I don't have that capability
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