SOLUTION: Write an equation in slope-intercept form for the line form that is perpendicular to 5x + 3y = 18 and passes through the origin.

Question 906306: Write an equation in slope-intercept form for the line form that is perpendicular to 5x + 3y = 18 and passes through the origin.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
the standard slope-intercept form for an equation of a line is
where m is the slope and b the y-intercept.
5x + 3y = 18 0r y = (-5/3)x + 6, m = (-5/3)
New line: m = as (I think of 3/5 as the negative reciprocal of -5/3)
***Using point-slope form, P(0,0)
y-0 = (3/5)(x-0)
y = (3/5)x in slope-intercept form
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