SOLUTION: 56) Number problems. Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin does she have?
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Question 89733: 56) Number problems. Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin does she have?
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
n+d=50 or n=50-d
5n+10d=350 now substitute (50-d) for n in this equation & solve for d:
5(50-d)+10d=350
250-5d+10d=350
5d=350-250
5d=100
d=20 number of dimes.
50-20=30 number of nickles.
proof
5*30=10*20=350
150+200=350
350=350
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