SOLUTION: 1. A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min nap. Upon awakening, he remembers the race and ru

Question 888663: 1. A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km
and then stops for a 90.0-min nap. Upon awakening, he remembers the race and runs twice as
fast. Finishing the course in a total time of 1.75 h, the rabbit wins the race. (a) Calculate the
average speed of the rabbit. (b) What was his average speed before he stopped for a nap?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
1.75 h=60+45=105 minutes
105-90=15 minutes running
4/1.75 =2.2857 kmph average for the 1.75 hours
per hour
a+b=.25
r*a=.5
2r*b=3.5
a=0.0555556 hr b, b=0.194444 hr, r=9 kph before his nap.
per minute
a+b=15
r*a=.5
2r*b=3.5
a=3.33333 minutes before nap, b=11.6667 minutes after nap, r=0.15 km per minute before his nap

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