SOLUTION: Solve the equation by-
1.substitution method
2.elementation method
3.cross multipication method
5x+3y=25
2x+4y=28
Algebra.Com
Question 881574: Solve the equation by-
1.substitution method
2.elementation method
3.cross multipication method
5x+3y=25
2x+4y=28
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
2x+4y=28 0r x+2y = 14,
5(14-2y) + 3y = 25
-7y =-45, y = 45/7 and x = 8/7
5x + 3y=25
x + 2y = 14 Mulitiply by -5 and Add to 1st EQ to eliminate x
-7y = -45, y = 45/7 and x = 8/7
will Let You finish
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