SOLUTION: Please help and explain how you came up with the answer. For some reason I continue to do something wrong when solving these particular problems.
Write the equation of the line
Question 879587: Please help and explain how you came up with the answer. For some reason I continue to do something wrong when solving these particular problems.
Write the equation of the line perpendicular to 3x-y=6 and passing through (4,1). I am being asked to answer the equation in standard form. Found 2 solutions by ewatrrr, josgarithmetic:Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi
line perpendicular to , m = 3
New line: m = (-1/3) thru P(4,1)
***Using point-slope form,
y -1 = (-1/3)(x-4)
y = (-1/3)x + 4/3 + 1
y = (-1/3)x + 7/3
or
x + 3y = 7 in standard form
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website! Get to know standard form for a line.
Ax+By=C can be solved for y and then the slope can be seen. You will find that is the slope. The slope of a line perpendicular would be the negative reciprocal of that, or . What this means for the right hand member of standard form equation is either or .
The value of C will be different and depends on a point which the perpendicular line sought contains. Substitute this point for x and y and compute C.
In your example, .
Substitute the given needed point:
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Equation x+3y=7 is perpendicular to 3x-y=6.