SOLUTION: I have been trying for days now to solve this problem. It is really tricky because I got the top but not the bottom or I got the bottom nuber but not the to. I need help!!! The pro

Question 87837: I have been trying for days now to solve this problem. It is really tricky because I got the top but not the bottom or I got the bottom nuber but not the to. I need help!!! The problem goes like this: Determine k so that the line through(k+2,k) and (3,2) has slope of 3. Can you explain to me how to do it?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You can start with the formula for finding the slope, m, of a line that passes through two points, (x1, y1) and (x2, y2):

You are given the slope, m = 3.
And the two points are:
(x1, y1) = (k+2, k) and
(x2, y2) = (3, 2)
Now if you substitute the given values into the formula, you can solve for k.
Simplify this.
Notice the change of sign on the 2 in the denominator.
Now multiply both sides by (1-k).
Apply the distributive property on the left side.
Add 3k to both sides.
Subtract 2 from both sides.
Finally, divide both sides by 2.

Answer is:

Let's check the answer by substituting into the slope formula.
Simplifying this, we get:

...and this is the expected slope!
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