SOLUTION: The perpendicular given passing through a point
y = 3x + 3; (1, 1)
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Question 869739: The perpendicular given passing through a point
y = 3x + 3; (1, 1)
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
y = 3 x + 3
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = 3
The slope of a line perpendicular to the above line will be the negative reciprocal - 1/3
Because m1*m2 =-1
The slope of the required line will be - 1/3
m= - 1/3 ,point ( 1 , 1 )
Find b by plugging the values of m & the point in
y=mx+b
1 = - 1/ 3 + b
b= 4/3
m= - 1/3
The required equation is y = - 1/ 3 x + 4/ 3
m.ananth@hotmail.ca
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