SOLUTION: find the slope intercept form (y=mx+b) of the equation for the line that satisfy the following: passes through (5, -9) and is perpendicular to the line whose equation is y=1/7x +4

Question 86854: find the slope intercept form (y=mx+b) of the equation for the line that satisfy the following:
passes through (5, -9) and is perpendicular to the line whose equation is y=1/7x +4

Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
Question:

find the slope intercept form (y=mx+b) of the equation for the line that satisfy the following:
passes through (5, -9) and is perpendicular to the line whose equation is y=1/7x +4

Answer:

Equation of the required equation is given by the formula,

(y - y1) = m ( x- x1)

Here (x1, y1) = (5, -9)

Required line is perpendicular to

Slope of this line is

So slope of the required line is = ,
since these lines are perpendicular to each other, the product of their slopes should be -1

==> slope of the required line = -7

So equation of the rquired line,

==> ( y - (-5) = -7 ( x - 5)

==> y + 5 = -7x + 35

Subtract 5 from both sides.

==> y + 5 - 5 = -7x + 35 - 5

==> y = -7x + 30
Which is the required equation.

Hope you found the explanation useful.

Warm Regards.

Praseena.

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