SOLUTION: given this equation y-3=3(x+1), what is the equation in standard form of a perpendicular line that passes thru (5,1) and what is the x intercept of the perpendicular line
Algebra.Com
Question 864279: given this equation y-3=3(x+1), what is the equation in standard form of a perpendicular line that passes thru (5,1) and what is the x intercept of the perpendicular line
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
given this equation y-3=3(x+1), what is the equation in standard form of a perpendicular line that passes thru (5,1) and what is the x intercept of the perpendicular line.
***
standard form of equation for a line: y=mx+b, m=slope, b=y-intercept
equation of given line:
y-3=3(x+1)
y-3=3x+3
y=3x+6
slope=3
..
slope of line perpendicular to given line=-1/3 (negative reciprocal)
equation of perpendicular line: y=(-1/3)x+b=-x/3+b
solve for b using coordinates of given point (5,1)
1=-1*5/3+b
b=8/3
equation: y=-x/3+8/3
find x-intercept:
set y=0
-x/3+8/3=0
x/3=8/3
x=8
x-intercept=8
RELATED QUESTIONS
for the equation y-3=3(x+1), i need to write an equation in standard form of a... (answered by richwmiller)
Use the point-slope form linear equation given to complete problems 5-18
Y- 3 = 3(x +... (answered by solver91311)
What is y-3=3(x+1) in standard form of a perpendicular line that passes through (5,... (answered by josgarithmetic)
what is the equation in standard form of a perpendicular line that passes through (5,1)... (answered by ikleyn)
parallel and perpendicular lines
i need to put my answer into slope - intercept form,y=... (answered by MathLover1,lwsshak3)
In advance I apologize for this long question and also thank you for helping me.
Use... (answered by josgarithmetic)
A line perpendicular to x + 3y = 5 passes through (1, -1). What is the equation of the... (answered by mananth)
Using the point slope linear equation, y + 4 = -4(x-2)....what is the equation in... (answered by ikleyn)
Not sure how to go about this other than turning the equation into y=mx+b, plug the... (answered by scott8148)