SOLUTION: 2). a triangle has a perimeter of 69 inches. the second side is 7 inches longer than the first side. the third side is 6 inches shorter than twice the length of the first side. fin
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Question 85916: 2). a triangle has a perimeter of 69 inches. the second side is 7 inches longer than the first side. the third side is 6 inches shorter than twice the length of the first side. find the length of each side.
Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
Question:
a triangle has a perimeter of 69 inches. the second side is 7 inches longer than the first side. the third side is 6 inches shorter than twice the length of the first side. find the length of each side.
Answer;
Assume that the first side = x inches
The the second side is = (x+7) inches
The third side = 2x - 6 inches
Perimeter = total length of its sides = 69 inches
That is sum of three sides will give the perimeter....
==> x + x + 7 + 2x - 6 = 69
Now collect the x terms together.....
==> x+ x+ 2x + 7 - 6 = 69
==> 4x + 1 = 69
Subtract 1 from both sides.
==> 4x + 1 - 1 = 69 -1
==> 4x = 68
Divide both sides by 4
==>
==> x = 17
That is length of the first side = 17 inches
So second side = x + 7 = 17 + 7 = 24 inches.
Third side = 2x - 6 = 2*17 - 6 = 34 - 6 =28 inches
Hope you found the explanation useful.
Regards.
Praseena.
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