SOLUTION: 1). the perimeter of a rectangle is 50 feet. the length is 11 feet more than width. what are the dimensions of the rectangle?
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Question 85911: 1). the perimeter of a rectangle is 50 feet. the length is 11 feet more than width. what are the dimensions of the rectangle?
Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
Question:
the perimeter of a rectangle is 50 feet. the length is 11 feet more than width. what are the dimensions of the rectangle?
Answer:
Assume that width = x feet.
Then length = x +11 feet( given that length is 11 feet more than width)
Perimeter = 2( length + width)
Given, perimeter = 50 feet.
==> 2( length + width) = 50
==> 2( x + 11 + x ) = 50
==> 2( 2x + 11) = 50
==> 2*2x + 2*11 = 50
==> 4x + 22 = 50
Subtract 22 from both sides.....
==> 4x + 22 -22 = 50 - 22
==> 4x = 28
Divide both sides of the expression by 4
==>
===> x = 7
That is width = 7 feet.
So, length = x + 11 = 7 + 11 = 18 feet.
You can check yopur answer by plugging the values of length and width in the given formula, perimeter = 2(length + width)
Hope you found the explanation useful.
Regards.
Praseena.
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