SOLUTION: {{{n+(1/8) - 2-(n/3) = (5/6)}}}
Algebra.Com
Question 84833:
Answer by Spec80(9) (Show Source): You can put this solution on YOUR website!
Your question seems to be asking to solve for n in the following:
The first step to doing this problem is to combine like terms, therefore we would do and
Then then need to get n by itself on one side and since right now it is AMP Parsing Error of [(2n/3]: Invalid expression. Closing bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 187.
.
we want to get that by itself. To do that, we will add to both sides, so the problem turns out to be:
Then, what we can do is cross multiply to get rid of the fractions, so what that means is we would do 24 x 2x and 3x65 . That makes the problem look like:
Finally we divide both sides by 48 to get n by itself, so the problem turns out to be:
RELATED QUESTIONS
{{{ (8*n^2-1)(3*n^2-4*n+5)... (answered by kingme18)
1. A(n)=-3+(n-1)(5)
2. A(n)=-11+(n-1)(2)
3. A(n)=9+(n-1)(8)
4. A(n)=0.5+(n-1)(3.5)
(answered by tommyt3rd)
1. A(n)=-3+(n-1)(5)
2. A(n)=-11+(n-1)(2)
3. A(n)=9+(n-1)(8)
4. A(n)=0.5+(n-1)(3.5)
(answered by tommyt3rd)
1. A(n)=-3+(n-1)(5)
2. A(n)=-11+(n-1)(2)
3. A(n)=9+(n-1)(8)
4. A(n)=0.5+(n-1)(3.5)
(answered by tommyt3rd)
solve.
( n + 3 /8 ) - ( n - 2 / 6 ) =... (answered by Nate)
n+1/8-2-n/3=5/6 completely comfused but I know LCD is... (answered by ewatrrr,josmiceli)
-7(5-n)=... (answered by jim_thompson5910)
find the sum of the geometric series
6
[SUM] 2^n
n=1
n=1 2^1=2
n=2 2^2=4
n=3 (answered by jim_thompson5910)
4(n+2)
------ = 3 - (n+6)... (answered by MathLover1)