SOLUTION: A line passes through (–2, –10) and (9, –4).
a. Write an equation for the line in point-slope form.
b. Rewrite the equation in standard form using integers.
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Question 846965: A line passes through (–2, –10) and (9, –4).
a. Write an equation for the line in point-slope form.
b. Rewrite the equation in standard form using integers.
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The formula for the slope is,
In point slope form,
Then to get to standard form,
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A line passes through (–2, –10) and (9, –4).
a. Write an equation for the line in point-slope form.
slope = (-4--10)/(9--2) = 6/11
Form: y = mx + b
Solve for "b":
-10 = (6/11)*-2 + b
-10 = -12/11 + b
b = -110/11 + 12/11
b = -98/11
Equation:
y = (6/11)x - (98/11)
----------------
b. Rewrite the equation in standard form using integers.
Multiply thru by 11 to get:
6x - 11y = 98
======================
Cheers,
Stan H.
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