SOLUTION: Solve the following linear system using the Echelon Method. x+2y− z= −1 2x − 3y + 2z = 15 −3x+ y+4z=−19

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Question 841119: Solve the following linear system using the Echelon Method.
x+2y− z= −1
2x − 3y + 2z = 15
−3x+ y+4z=−19

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Solve the following linear system using the Echelon Method.
x+2y− z= −1
2x − 3y + 2z = 15
−3x+ y+4z=−19
---------
Subtract 2 times 1st from 2nd
Add 3 times 1st to 3rd
-----------------------------------
x +2y − z = −1
0x -7y + 4z = 17
0x +7y + z = -22
-----------------------
Add the 2nd to the 3rd::
x +2y − z = −1
0x -7y + 4z = 17
0x +0y + 5z = -5
----------------------------
Solve the 3rd for "z"::
z = -1
---
Substitute for "z" in the 2nd and solve for "y":
0x - 7y -4 = 17
-7y = 21
y = -3
------
Substitute for "z" and for "y" in the 1st and solve for "x"::
x -6 + 1 = -1
x = 4
--------------------
Cheers,
Stan H.

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