SOLUTION: Solve each linear system using substitution.
3m-6n=1
m+3n= 2
Thank you.
Algebra.Com
Question 838725: Solve each linear system using substitution.
3m-6n=1
m+3n= 2
Thank you.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
3m-6n=1
m+3n= 2
m=2-3n
3(2-3n)-6n=1
6-9n-6n=1
6-15n=1
5=15n
5/15=n
1/3=n
m+3*(1/3)= 2
m+1=2
m=1
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