SOLUTION: What is the equation of the line through (0,9) that is parallel to the line 3x+5y=15?

Question 83081: What is the equation of the line through (0,9) that is parallel to the line 3x+5y=15?
Found 2 solutions by chitra, rapaljer:
Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
The given line equation is:

3x + 5y = 15

Writing this eqn in the form of y = mx + b, we get:

5y = -3x + 15

==>

==>

From the above equation, we can find that the slope is given by, m =

Let the equation of the line parallel to the given line be in the form

y = mx + b. It will have the same slope as that of the given line. Also given that the point (0,9) passess through the given line. Hence,

y = x + b

9 = (0) + b

==> b = 9

Thus, the equation of the requied line is:

y = - + 9

Hence, the solution.

Happy Calculating!!!

Regards,

Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
In order to find the equation of a line, you must know two things:
1) Slope
2) Y-intercept

In this problem, the slope must be found by writing the given equation in "slope-intercept" form. That is, you must solve for y in terms of x.
3x+5y=15
5y = -3x + 15

Divide both sides by 5:

The slope of the given line is m=-3/5, so the slope of any line PARALLEL to this line is also m=-3/5.

Secondly, the given point (0,9) just happens to be the Y-intercept, so in the equation
y=mx+b
m=-3/5 and b=9

R^2 at SCC
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