SOLUTION: write the equation of the circle in standard form. find the center, radius, intercepts, and graph the circle.
x^2+y^2-4x+18y=-69
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Question 829178: write the equation of the circle in standard form. find the center, radius, intercepts, and graph the circle.
x^2+y^2-4x+18y=-69
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
write the equation of the circle in standard form. find the center, radius, intercepts, and graph the circle.
x^2+y^2-4x+18y=-69
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[x^2-4x+4] + [y^2+18y+81] = -69+4+81
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(x-2)^2 + (y+9)^2 = 26
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Center: (2,-9)
Radius: sqrt(26)
Intercepts:
x-int = ?
Let y = 0; solve for "x":
(x-2)^2 = 26-81 = -55
Therefore: no x-intercepts
----
y-int = ?
Let x = 0; solve for "y":
(y+9)^2 = 26-4
y+9 = +-sqrt(22)
y = -9+-sqrt(22)
=====================
The graph cannot be shown on this site.
Cheers,
Stan H.
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