SOLUTION: Write the equation for the line that passes through the point (5,2) and is perpendicular to the graph of x+3y=7

Question 823531: Write the equation for the line that passes through the point (5,2) and is perpendicular to the graph of x+3y=7

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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x + 3y = 7
3y = -x + 7
y = (-1/3)x + 7/3
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perp lines have negative reciprocal slopes, so the perp slope = 3
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perp line contains (5,2)
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to solve the linear equation, copy and paste this (given point and perp slope):
5,2,3
into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
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x-intercept = (4.33333333, 0)
y-intercept = (0, -13)
slope = 3
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answer:
the slope-intercept form:
y = 3x - 13
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Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
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