SOLUTION: Find the equation, in standard form, of the line perpendicular to -5x+3y=3 that passes through the points (-8,-9). Write the equation in standard form.

Question 823381: Find the equation, in standard form, of the line perpendicular to -5x+3y=3 that passes through the points (-8,-9). Write the equation in standard form.

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
-5 x + 3 y = 3
Find the slope of this line

3 y = 5 x + 3
Divide by 3
y = 5/ 3 x + 1
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = 5/3

The slope of a line perpendicular to the above line will be the negative reciprocal - 3/5
Because m1*m2 =-1
The slope of the required line will be - 3/5

m= - 3/5 ,point ( -8 , -9 )
Find b by plugging the values of m & the point in
y=mx+b
-9 = 24/ 5 + b
b= -69/5
m= - 3/5
The required equation is y = - 3/ 5 x + -69/ 5
multiply by 5
5y=-3x-69
3x+5y=-69
m.ananth@hotmail.ca

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