SOLUTION: How do I find the slope of the line (2m,m) (4m,3m) where m can not be 0?

Algebra.Com
Question 823319: How do I find the slope of the line (2m,m) (4m,3m) where m can not be 0?

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
slope = (y2 - y1)/(x2 - x1)

slope = (3m - m)/(4m - 2m)

slope = (2m)/(2m)

slope = 1

So the slope is 1 where

RELATED QUESTIONS

6^3m*6^-m=6^-2m tried 3m*-m=-2m 3m+2m=-m but I think maybe 3m-2m-1m= 0 but... (answered by jim_thompson5910)
(2M-6)-(3m-4)= -(-4+M)-4M+6 i started the problem but I'm stuck i got to... (answered by jim_thompson5910,edjones)
Can someone help me with this, not sure how to go about this... Using the formula,... (answered by Nate)
Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m? -15m = (answered by josgarithmetic,rothauserc)
can someone help pretty please find the least common denominator. 17. 2m+3/m^2-25 and (answered by ewatrrr)
Here is the problem. Directions are to solve and check. 3m-(m+1)=6m+1 My work: 1st. (answered by rapaljer)
How do I multiply (3m + 2) ( 4m^2 - m... (answered by rfer)
I have a problem where I am supposed to write each rational expression in lowest terms... (answered by Earlsdon)
Find the sum of like terms. -4m + 3m +... (answered by Mathtut)