SOLUTION: What is the equation of the line described below written in slope-intercept form? the line passing through point (4, -1) and perpendicular to the line whose equation is 2x

SOLUTION: What is the equation of the line described below written in slope-intercept form? the line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y -

Question 822208: What is the equation of the line described below written in slope-intercept form?
the line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0

y = -x + 1
y = x - 1
y = 2x + 1
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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2x - y - 7 = 0
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put the linear equation in standard form
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2x - y = 7
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the above linear equation is in standard form, with a=2, b=-1, and c=7
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to solve the linear equation, copy and paste this:
2 -1 7
into the "Standard form: A B C" input box here: https://sooeet.com/math/linear-equation-solver.php
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answer:
x-intercept = (3.5, 0)
y-intercept = (0, -7)
slope = 2
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perpendicular lines have negative reciprocal slopes, so the perpendicular slope is: -1/2
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solve for the line passing through (4, -1) with slope -1/2:
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to solve the linear equation, copy and paste this (the given point and the perpendicular slope):
4 -1 -0.5
into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
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answer:
x-intercept = (2, 0)
y-intercept = (0, 1)
slope = -0.5
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answer:
the slope-intercept form is:
y = (-1/2)x + 1
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Solve and graph linear equations:
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
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