SOLUTION: I'm super lost on this one, can anyone help me solve? Divide: 24m(4)n(2) � 8m(2)n(3) + 4m(3)n/4m(2)n

Question 81696: I'm super lost on this one, can anyone help me solve?
Divide: 24m(4)n(2) � 8m(2)n(3) + 4m(3)n/4m(2)n

Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
24m^4n^2-8m^2n^3+4m^3n/4m^2n because you have a fraction with a denominator of (4m^2n) we need to multiply all other terms by (4m^2n) so we can combine there terms.
[(24m^4n^2)(4m^2n)-(8m^2n^3)(4m^2n)+(4m^3n)]/4m^2n
(96m^6n^3-32m^4n^4+4m^3n)/4m^2n now we cancel wherever possible:
(14m^4n^2-8m^2n^3+m) Noe we extract all common elements thus:
m(14m^3n^2-8mn^3+1) ANSWER.
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