SOLUTION: Hello I am having trouble with my gaussian elimination homework. It is not the Jordan Gauss as in the matrix you want to end with two zeros in one row and one zero in another. Thi

Question 812364: Hello I am having trouble with my gaussian elimination homework.
It is not the Jordan Gauss as in the matrix you want to end with two zeros in one row and one zero in another. This is using three equations
The equation:
12x + 2y + 2z = 12
60x + 12y + 24z = 48
4x + y - z = -2
Please help ASAP it is due tomorrow
Answer by luke94(89) (Show Source): You can put this solution on YOUR website!
so as stated must have two zeros in one row and one in another such as the bottom left corner to make the matrix an upper triangle.. i will try answer this without making it to messy..
1. setup augmented matrix:
[A|b] = |12 2 2 |12|
|60 12 24|48|
|4 1 -1|-2|
2. apply row operations:
|12 2 2 |12|
|60 12 24|48|R2 = R2 - 5R1
|4 1 -1|-2|R3 = 3R3 - R1
---
|12 2 2 |12 |
|0 2 14|-12 |
|0 1 -5|-18 |R3 = 2R3 - R2
---
|12 2 2 |12 |
|0 2 14 |-12 |
|0 0 -24|-18 |STOP: upper triangle matrix (three 0's in bottom left)
---
now solve it start by backwards substitution.. find your Z value then Y then X
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