SOLUTION: please! someone could help me.. i'm really out of idea how can i solve out this problem. Find the equation of the straight line perpendiculat to the line with equation y= -2/3x

Question 8060: please! someone could help me.. i'm really out of idea how can i solve out this problem.
Find the equation of the straight line perpendiculat to the line with equation y= -2/3x + 3/7 which passes through the point (2,4). giving your answer in the form ax+by+c=0
please.. help me solve this..
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
the line defined by y= -2/3x + 3/7 has gradient -2/3.

Any line perpendicular to this has a gradient to 3/2. So, we know the equation we want is y = (3/2)x + c.

We now need the specific equation for that line passing through (2,4), so we then get 4 =(3/2)2 + c which gives 4 = 3 + c. In other words c = 1.

So the equation is y = (3/2)x + 1

Now, you don't say if a,b and c are integers?

If not: y - (3/2)x - 1 = 0
If whole numbers, just multiply all terms by 2:
--> 2y - 3x - 2 = 0

jon.

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