SOLUTION: I need to find an equation that passes through (4,-2) and is perpendicular to x=5/4y-2. I know that I need to first set the equation equal to zero so that I can find the slope. To
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Question 798904: I need to find an equation that passes through (4,-2) and is perpendicular to x=5/4y-2. I know that I need to first set the equation equal to zero so that I can find the slope. To get rid of the fraction do I multiply everything by 4?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I need to find an equation that passes through (4,-2) and is perpendicular to x=5/4y-2. I know that I need to first set the equation equal to zero so that I can find the slope. To get rid of the fraction do I multiply everything by 4?
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x=(5/4)y-2
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(5/4)y = x+2
y = (4/5)x + (4/5)2
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y = (4/5)x + (8/5)
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slope of given line = 4/5
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slope of perpendicular line = -5/4
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Form: y = mx + b
Solve for b using m = -5/4, x = 4, y = -2
-2 = (-5/4)*(4) + b
b = 3
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Equation:
y = (-5/4)x + 3
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Cheers,
Stan H.
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