SOLUTION: Complete the ordered pairs so that each is a solution for the given equation. 3x+4y=12 (0,_), (_,3/4), (_,0), (8/3,_) I do not have a clue as to where to start with this problem.

Question 79384: Complete the ordered pairs so that each is a solution for the given equation.
3x+4y=12 (0,_), (_,3/4), (_,0), (8/3,_) I do not have a clue as to where to start with this problem. I would really appreciate it if someone would please explain it step by step to help me understand the problem.
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
In ordered pairs, the first number is always the x-term and the second number is always the y-term. So (x, y) can be (1, 0) and the x=1; y=0
.
In this problem, identify either the x or the y-term, plug it into the problem and solve for the missing term:
.
(0,_), so x=0 and the y-term is missing:
3x+4y=12
3(0)+4y=12
0+4y=12
4y=12
4y/4=12/4
y=3
So, the point is (0,3)
.
(_,3/4), so the x-term is missing and y=3/4
3x+4(3/4)=12
3x+3=12
3x+3-3=12-2
3x=9
3x/3=9/3
x=3
So, the point is (3, 3/4)
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