SOLUTION: Find the value of m in the equation y=mx+3, such that (-2,5) is on the graph.

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Question 79242: Find the value of m in the equation y=mx+3, such that (-2,5) is on the graph.
Found 2 solutions by tutorcecilia, Edwin McCravy:
Answer by tutorcecilia(2152)   (Show Source): You can put this solution on YOUR website!
y=mx+3 [slope-intercept equation of the line]
5=m(-2)+3 [substitute the values of x=-2 and y=5; and solve for the m-term]
5-3=-2m+3-3
2=-2m
2/-2=-2m/2
-1=m
.
check by plugging all of the values back into the original equation and solve]
y=mx+3 [original equatino]
(5)=(-1)(-2)+3
5=2+3
5=5 [checks out]
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!

Find the value of m in the equation y=mx+3, 
such that (-2,5) is on the graph.


Rule: If a point (1st number, 2nd number) is
on the graph of an equation containg a missing
letter OTHER than x or y, then you 
substitute the 1st number for x and the
2nd number for y into the equation and
solve for that missing letter:

 
     y = mx + 3

So we substitute -2 for x and 3 for y

     5 = m(-2) + 3

     5 = -2m + 3

Add 2m to both sides

2m + 5 = 3

Subtract 5 from both sides

    2m = -2

Divide both sides by 2

    

     m = -1

Edwin
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