SOLUTION: The directions are 'write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.' The equation is (

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Question 790141: The directions are 'write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.' The equation is (-1,3);y=2x-8
Answer by fcabanski(1391)   (Show Source): You can put this solution on YOUR website!
Slope intercept form of a line is y=mx+b where m is the slope.


Parallel lines have = slopes. y=2x-8 has a slope, m = 2. So the slope of the parallel line is 2.


The point slope form of a graph is y-y(1) = m(x-x(1)) where x(1),y(1) is a point on the line. The problem states (-1,3) is on the line.


We know the slope, 2, and the point (x(1),y(1)) = (-1,3)


y-3 = 2(x-(-1) = y-3 = 2(x+1) = y-3 = 2x + 2


y = 2x + 5



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